find area of triangle whose b is 3/5 and h is 2/3
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Answer:
area of triangle=½×b×h
b=⅗ and h=⅔
Therefore,Area of the given triangle is ½×⅗×⅔=⅕=0.2
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GIVEN :
base of ∆ = 3/5
height of ∆ = 2/3
TO FIND :
the area of triangle (∆)
FORMULA USED:
area of ∆ = 1/2 × base (b) × height (h)
area of ∆ = 1/2 × 3/5 × 2/3
area of ∆ = 1/5 square unit
ANSWER : area of triangle = 1/5 (or 0.2 ) square unit
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