Question

find area of triangle whose sides are 56,52,12 using herons formula​

Answer 1

Answer:

Side,

A=56,

B=52,

C=12.

Now,find the semi perimeter of triangle.

Semi-perimeter=A+B+C÷2

'' =56+52+12÷2

'' =120÷2

'' =60

Now, semi perimeter is = 60,

Here _/means=whole root(Only for explanation)

Area of triangle using herons formula=_/S(S-A)(S-B)(S-C)

Area of triangle =_/60(60-56)(60-52)

(60-12)

" =_/60(4)(8)(48)

{ Now we will make pairs by breaking values into simplest form}

Area of triangle =_/(2×2×3×2×5)(2×2)

(2×2×2)(2×2×2×2×3)

{If you don't understand self multiply values in brackets.}

Area of triangle =_/2×2××3×2×5×2×2×2

2×2×2×2×3

[Now arrange in sequence of same value]

Area of triangle =_/2×2×2×2×2×2×2×2×2×

3×3×5

[Now make pairs and take common and bring out of root which are not in pair let them in]

Area of triangle =2×2×2×3_/2×5

" " = 24_/10

Now, the answer is=24_/10