find area of triangle whose sides are 56,52,12 using herons formula
Answers
Answer:
Side,
A=56,
B=52,
C=12.
Now,find the semi perimeter of triangle.
Semi-perimeter=A+B+C÷2
'' =56+52+12÷2
'' =120÷2
'' =60
Now, semi perimeter is = 60,
Here _/means=whole root(Only for explanation)
Area of triangle using herons formula=_/S(S-A)(S-B)(S-C)
Area of triangle =_/60(60-56)(60-52)
(60-12)
" =_/60(4)(8)(48)
{ Now we will make pairs by breaking values into simplest form}
Area of triangle =_/(2×2×3×2×5)(2×2)
(2×2×2)(2×2×2×2×3)
{If you don't understand self multiply values in brackets.}
Area of triangle =_/2×2××3×2×5×2×2×2
2×2×2×2×3
[Now arrange in sequence of same value]
Area of triangle =_/2×2×2×2×2×2×2×2×2×
3×3×5
[Now make pairs and take common and bring out of root which are not in pair let them in]
Area of triangle =2×2×2×3_/2×5
" " = 24_/10
Now, the answer is=24_/10