Question

find area of triangle whose sides are 6 +x,8 + X and 14 by heron's formula

Answer 1

$heya \\ \\ \\ herons \: formula \: \\ \\ \\ \sqrt{s(s - a)(s - b)(s - c)} \\ \\ s = (28 + 2x) \div 2 \\ \\ s = 14 + x \\ \\ \\ area \: of \: trangle \: is \: \\ \\ \\ \sqrt{14 + x \times (8)(6)(x)} \\ \\ \sqrt{14 + x \times (48x)} \\ \\ \sqrt{672x + 48x {}^{2} } square \: units$