Question

find area of triangle whose sides are 8 CM 11 cm and 13 cm and the semi perimeter is 32cm

Answer 1

semi perimeter = perimeter (a+b+c)/2

i.e, 32/2=16

area of triangle= √s(s-a)(s-b)(s-c)

= √16*4*5*3

=√4*4*4*5*3

= 4*2√15

=8√15cm²

Hope it helps you !!!!

Answer 2

Answer:

Area of triangle =√(s(s-a) (s-b) (s-c))

=√(32(32-8)(32-11)(32-13))

=√(32(24)(21)(19))