Question

find area of triangle whose vertices are (2,3) (0,2) (-1,2)

please solve it​

Answer 1

Answer:

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Answer 2

Answer:

Area of triangle with 3 points is:

A=1/2|x1(y2−y3)+x2(y3−y1)+x3(y1−y2)|

Step-by-step explanation:

by putting the value of :

x1 = 2 , y1 = 3,

x2 = 0, y2 = 2,

x3 = -1, y3 =2

Area =1/2 |2(2-2) + 0 + (-1)(3-2)|

= 1/2|0+0-1|

= 1/2