Question

Find area of triangle whose vertices are (4,3) , (1 ,4) & (2,3) *

Answer 1

Step-by-step explanation:

Given :-

The points (4,3) , (1 ,4) , (2,3)

To find :-

Area of a triangle formed by the vertices

Solution :-

Given points are (4,3) , (1 ,4) , (2,3)

Let (x1, y1) = (4,3) => x1 = 4 and y1 = 3

Let (x2, y2) = (1,4) => x2 = 1 and y2 = 4

Let (x3, y3) = (2,3) => x3 = 2 and y3 = 3

We know that

Area of a triangle formed by the vertices (x1,y1) , (x2, y2) and (x3, y3) is ∆ = (1/2) | x1(y2-y3)+x2(y3-y1)+x3(y1-y2) | sq.units

Now,

Area of the given triangle formed by the given vertices is

∆= (1/2) | 4(4-3)+1(3-3)+2(3-4) | sq.units

=> ∆ = (1/2) | 4(1) + 1(0) + 2(-1) |

=> ∆ = (1/2) | 4+0-2 |

=> ∆ = (1/2) | 4-2 |

=> ∆ = (1/2) | 2 |

=> ∆ = (1/2)×2

=> ∆ = 2/2

=> ∆ = 1 sq.units

Therefore, Area of the triangle = 1 sq.units

Answer :-

Area of the given triangle is 1 sq.units

Used formulae:-

Area of a triangle formed by the vertices (x1,y1) , (x2, y2) and (x3, y3) is ∆ = (1/2) | x1(y2-y3)+x2(y3-y1)+x3(y1-y2) | sq.units

Answer 2

Step-by-step explanation:

Step-by-step explanation:

Given :-

The points (4,3) , (1 ,4) , (2,3)

To find :-

Area of a triangle formed by the vertices

Solution :-

Given points are (4,3) , (1 ,4) , (2,3)

Let (x1, y1) = (4,3) => x1 = 4 and y1 = 3

Let (x2, y2) = (1,4) => x2 = 1 and y2 = 4

Let (x3, y3) = (2,3) => x3 = 2 and y3 = 3

We know that

Area of a triangle formed by the vertices (x1,y1) , (x2, y2) and (x3, y3) is ∆ = (1/2) | x1(y2-y3)+x2(y3-y1)+x3(y1-y2) | sq.units

Now,

Area of the given triangle formed by the given vertices is

∆= (1/2) | 4(4-3)+1(3-3)+2(3-4) | sq.units

=> ∆ = (1/2) | 4(1) + 1(0) + 2(-1) |

=> ∆ = (1/2) | 4+0-2 |

=> ∆ = (1/2) | 4-2 |

=> ∆ = (1/2) | 2 |

=> ∆ = (1/2)×2

=> ∆ = 2/2

=> ∆ = 1 sq.units

Therefore, Area of the triangle = 1 sq.units