Question

find area of triangle with side 24cm,26cmand 10cm​

Answer 1

Answer:

The sides of the triangle being 10 cm, 24 cm and 26 cm, we can find the area by

Heron’s formula. Here S, semi perimeter = [10+24+26}/2 = 30, So area of the triangle is A = [s(s-a)(s-b)(s-c)]^0.5 or

= [30(30–10)(30–24)(30–26)]^0.5

= [30*20*6*4]^0.5

= [100*6*6*2*2]^0.5

= 10*6*2 = 120 sq cm.

Alternately, 10=24=26 is a RAT with 26 as the hypotenuse, so the area of the RAT = 24*10/2 = 120 sq

Answer 2

$\huge\purple{✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏}$

$\orange{★★★★☆☆☆✯☆☆☆★★★★}$

$\huge\underline\green{✎﹏Question༉}$

✯ Find area of triangle with side 24cm,26cmand 10cm.

$\huge\underline\blue{✎﹏Solution༉}$

$\underline\red{✧Given\:sides\:are;\:24cm\:26cm\:10cm}$

➥Semi-perimeter = a + b + c/2

$\: \: \: \: \: \: \: \: \ \: \: \: \: \: \: \: \: \: \: \: = > \frac{24 + 26 + 10}{2}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > \frac{60}{2}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = >30cm$

$\underline\red{✧Now,\:Area\: of \:\:triangle\:is;}$

$area = > \sqrt{s(s - a)(s - b)(s - c) } \\ = > \sqrt{30(30 - 24) (30 - 26) (30 - 10) } \\ = > \sqrt{30 \times 6 \times 4 \times 20} \\ = > \sqrt{30 \times 480} \\ = > \sqrt{1440 0} \\ \: \: \: \: \: \: \: \: \: \: = > \sqrt{120 \times 120} \\ \: = > 120$

$\underline\red{❥So,\:The\:area\:of \:triangle\:is\:120cm}$

$\orange{★★★★☆☆☆✯☆☆☆★★★★}$

$\underline\pink{✫Hope,\:it\:Helps \:You࿐}$

$\huge\purple{✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏}$