Question

Find area of triangular park whose sides are 120cm, 80cm and 50 cm

Answer 1

sides of park = 120cm,80cm,50cm

a=120,b=80,c=50

now peremeter = 120 +80+50

=250cm

now, s =peremeter/2

s = 250/2

s= 125

Heron's formula = √s (s-a)(s-b)(s-c)

= √125(125-120)(125-80)(125-50)

=. √5*5*5*5*45*75

=. √5² * 5² * 3*3*5*3*5*5

=. √ 5² * 5² * 3² * 5² * 3* 5

=. 5*5*3*5 √ 3*5

=. 375√15 cm²

hope this answer helps u...........

Answer 2

Answer:

375root5

Step-by-step explanation: semiperimeter of park = a+b+c/2

                                                                          = 120+80+50/2 =125

area= root(s)(s-a)(s-b)(s-c)

        =root(125)(125-120)(125-80)(125-50)

        =root(5*5*5)(5)(3*3*5)(3*5*5)

       = (5*5*5*3)root3*5

       = 375root15

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