Question

find area (triangle ABC) if B=90°, A=16 cm C = 20 cm​

Answer 1

Answer:

In ∆ ABC , angle B=90° , angle C= 60° , angle A=30° and BC=12 cm. , applying

sine rule:-

AB/sinC = BC/sinA = CA/sinB.

or. AB/sin60° = 12/sin30°= CA/sin90°.

or. 2.AB/√3. = 2.12/1= CA/1.

or. AB = 12√3 cm. , CA(hypotenuse) = 24cm.

Area of triangle ABC = (1/2)×AB×BC = (1/2)× 12√3×12

= 72√3 cm^2. = 124.704 cm^2. Answer.

Step-by-step explanation:

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Answer 2

✯ Solution :-

By the given information ∆ABC is a right ∆

As we know that ,

• Area of ∆ = 1/2 × base × height

Here ,

• Base = C = 20cm
• Height = A = 16cm

Substituting ,

⇒ Area of ∆ = 1/2 × 16 × 20

⇒ Area of ∆ = 16 × 10

⇒ Area of ∆ = 160 m²

Hence , area of ∆ABC = 160m²

✯ More information :-

Formulas ,

• Area of Equilateral triangle = √3/2 a²
• Perimeter of ∆ = sum of all sides
• Area of rectangle = l × b
• Area of square = S²
• Perimeter of rectangle = 2(l + b)
• Perimeter of square = 4S