Question

❤❤❤ Find area under the curve y = sin x from x = pie to x = 2 pie ?? ❤❤❤​

Answer 1

Answer:

Given,

${\bf{\green{y=sinx}}}$

${\bf{\red{=> ∫π^2πydx}}}$

${\bf{\blue{=>∫π^2πsinXdx}}}$

${\bf{\pink{=>(-cosx)π^2π}}}$

${\bf{\green{=>-(cos2π-cosπ) }}}$

${\bf{\orange{=>-(1-(-1))}}}$

${\bf{\blue{=>-(1+1)}}}$

${\bf{\red{=>-2}}}$

Answer 2

See the attachment ................