Find arithmetic mean of two positive numbers whose geometric mean and harmonic mean are 4 and 16/5 respectively
Answers
Answered by
0
Answer:
G^2=AH
4^2=A*16/5
16=A*16/5
16(5/16)=A
5=A
A=5
Answered by
0
Answer:
5
Step-by-step explanation:
Let say two numbers are
A & B
to find AM = (A + B)/2
GM = √AB = 4
=> AB = 16
HM = 2/(1/A + 1/B) = 16/5
=> 2AB/( B + A) = 16/5
=> 5AB / 16 = (A + B)/2
=> 5 * 16 / 16 = (A + B)/2
=> (A + B)/2 = 5
arithmetic mean of two positive numbers whose geometric mean and harmonic mean are 4 and 16/5 respectively = 5
Additional info
AB = 16
A + B = 10
=> x² - 10x + 16 = 0
=> x = 2 & 8
numbers are 2 & 8
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