Question

Find, as surds, the roots of the equation:
2(x+1)(x-4)-(x-2)^2=0.

Answer 1

Answer:

2(x+1)(x-4)-(x-2)²=0

2[x(x-4)+1(x-4)] - x²+2²-2×x×2

2(x²-4x+x-4) - x²+4-4x

2(x²-3x-4) - x²-4x+4

2x²-6x-8 - x²-4x+4

x²-10x-4

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