Find at least 3 solutions of the following linear equation in
two variables
2X+Y=12.
Answers
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Answer:
2x + 5y = 13
2x + 5y = 13
rightwards double arrow 5y = 13 - 2x
rightwards double arrow straight y equals fraction numerator 13 minus 2 straight x over denominator 5 end fraction
Put x = 0, then straight y equals fraction numerator 13 minus 2 left parenthesis 0 right parenthesis over denominator 5 end fraction equals 13 over 5
Put x = 1, then y equals fraction numerator 13 minus 2 left parenthesis 1 right parenthesis over denominator 5 end fraction equals 11 over 5
Put x = 2, then straight y equals fraction numerator 13 minus 2 left parenthesis 2 right parenthesis over denominator 5 end fraction equals 9 over 5
Put x = 3, then straight y equals fraction numerator 13 minus 2 left parenthesis 3 right parenthesis over denominator 5 end fraction equals 7 over 5
therefore space space space open parentheses 0 comma space 13 over 5 close parentheses comma space open parentheses 1 comma space 11 over 5 close parentheses comma space open parentheses 2 comma space 9 over 5 close parentheses space a n d space space open parentheses 3 comma space 7 over 5 close parentheses are the solutions of equation 2x + 5y = 13.