Question

find at least five answers of the equation 3x + 4y= 12 ​

Answer 1

3x + 4y = 12

when we give x =0

equation becomes,

3×0 + 4y = 12

= 4y =12

= y = 12/4

= y = 3

therefore the quardinates are (0,3)

when we give y=0

equation becomes,

3x+4×0=12

= 3x = 12

= x = 12/3

= x=4

therefore the quardinates are (4,0)

when we give x=1

the equation becomes,

3×1+4y=12

3+4y= 12

4y = 12-3

4y =9

y = 9/4

therefore the quardinates are (1,9/4)

when we give y=1

the equation becomes,

3x+4×1=12

3x+4=12

3x=12-4

3x=8

x=8/3

therefore the quardinates are (8/3,1)

when we give x=2

the equation becomes,

3×2+4y=12

6+4y=12

4y=12-6

4y =6

y=6/4

= 3/2

therefore the quardinates are (2,3/2)

hope this will help you