Question

Find at least three solutions of each the following equations
3x-y+8=0

Answer 1

3x-y+8=0

y = 3x + 8

If x = 1, then y = 3(1) + 8 = 11     ⇒  (1, 11) is a solution.
If x = 0, then y = 3(0) + 8 = 8     ⇒  (0, 8) is a solution.
If x = -1, then y = 3(-1) + 8 = 5     ⇒  (-1, 5) is a solution.

Answer 2

          Find at least three solutions of each the following equations ;-  
                                    ⇒3 x - y + 8 = 0


⇒Here we need to find any three solution  of  {- 3 x - y + 8 = 0 }, 

⇒ To do this equation , let us first rearrange the equation - 

                        ⇒ we get the result as,

                        ⇒ y =  3 x + 8

⇒ Now let us find the three solutions for it -
                                                           { Note ; you can take any value in                                                                                       x to find out y}

If x = 5 ,
                                           1⇒       {  5 , 23 }
then y = 3 ( 5 ) + 8 = 23  

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If x = 10 ,
                                           2⇒       { 10 , 38 }
then y = 3 ( 10 ) + 8 = 38

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If x = 15
                                           3⇒           { 15 , 53 }
then y = 3 ( 15 ) + 8 = 53

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