find at what time between 8 and 9o'clock will the hands of a clock be in the same straight line but not together.
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Step-by-step explanation:
In this type of problems the formulae is (5x−30)×1211
x is replaced by the first interval of given time Here i.e 8
(5*8−30)*1211
= 12011min
Therefore the hands will be in the same straight line but not
together at 12011 min.past 8.
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