Question

find atoms in 35.5 g of mg?​

Answer 1

Not all the scientists are free at the moment

Answer 2

Answer:

to find- no. of atoms in 35.5g of Magnesium

we know- no. of atoms=(given mass/molar mass)/avagadro's number

so, given mass of Mg=35.5g

Molar mass of Mg=55g

avagadro number=6.022*10^23

=35.5/55*6.022*10^23

=0.645*6.022*10^23

=3.88*10^23

thus, there are a total of 3.88*10^23 atoms in 35.5 g of Mg.

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