Math, asked by sonimishra150793, 11 months ago

find average 32/2,53/10,21/5,71/10​

Answers

Answered by nawal1740101
0

Answer:

8.15.

Step-by-step explanation:

32/2= 16

53/10= 5.3

21/5= 4.2

71/10= 7.1

average = (16+5.3+4.2+7.1)÷4

= 32.6÷4

= 8.15

Answered by amikkr
0

The average of the numbers is 8.15.

  • Given numbers is 32/2 , 53/10 , 21/5 , 71/10
  • To find the average of numbers we need to find the sum of all the numbers divided by the count ot terms.
  • Sum of numbers = \frac{32}{2}  + \frac{53}{10}  + \frac{21}{5} + \frac{71}{10}
  • LCM of the denominator is 10.

Sum =  \frac{32*5 + 53+21*2 +71}{10}

Sum = \frac{163}{5}

Sum = 32.6

  • No. of terms = 4
  • Average = [tex]\frac{32.6}{4}[\tex]

Average = 8.15

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