find average speed of train

Answers
Answer:
Total distance = 192 km.
Let the average speed of the fast train be x km/h.
Slow train = (x - 16)km/h
Time taken by fast train = (192/x) h
Time taken by slow train = {192/(x-16)} h
According to the question,
192/(x-16) - 192/x = 2
192[ 1/(x-16) - 1/x] = 2
192[ x - x + 16/ x² - 16x] = 2
192(16) = 2(x²-16x)
192(8) = x²-16x
1536 = x²-16x
x²-16x - 1536 = 0
x² - 48x + 32x - 1536 = 0
x(x-48) + 32(x-48) = 0
(x+32)(x-48)=0
Negative value will be neglected.
x = 48 km/h
Fast train average speed = 48km/h
Slow train average speed = 48-16 = 32km/h
Hope it helps..!! ^_^
Answer:
speed of the faster train is 48 km/hr.
speed of the slower train is 32 km/hr.
Step-by-step explanation:
Distance=192
t s=t
t f=t-2
S s=x-16
S f=x
t-(t-2)=(192/x-16)-(192/x)
2=(192x-192x+3072)/(x²-16x)
2x²-32x-3072=0
x²-16x-1536=0
x²+32x-48x-1536=0
x(x+32)-48(x+32)=0
(x-48)(x+32)=0
x=48 ; x=-32
speed could not be negative. so, x=48.
please mark this answer as brainliest, so that I can get motivated to solve many problems like this.