Question

Find Ax B, Ax A and B x A (i) A={2, -2,3} and B={1,-4}

Answer 1

Answer:

Given,

AX=B

[

2

4

4

3

][

n

1

]=[

8

11

]

upon performing multiplication operation, we get,

[

2n+4

4n+3

]=[

8

11

]

equating LHS and RHS, we get,

2n+4=8→2n=4⇒n=2

OR

4n+3=11→4n=8⇒n=2

∴

n=2

Answer 2

Answer:

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