Find axb. given a 21+4j+3k and b=21+4-4k
Answers
Answered by
0
Explanation:
Consider the vector
A
=2
i
^
+3
j
^
−4
k
^
And
B
=5
i
^
+2
j
^
+4
k
^
Now, as we know
A
.
B
=ABcosθ
θ is the angle between
A
and
B
Therefore,
cosθ=
AB
A
.
B
cosθ=
2
2
+3
2
+(−4)
2
5
2
+2
2
+4
2
(2
i
^
+3
j
^
−4
k
^
).(5
i
^
+2
j
^
+4
k
^
)
=
2
2
+3
2
+(−4)
2
5
2
+2
2
+4
2
(10+6−16)
=0
Therefore, cosθ=0
θ=90
∘
Hence angle between the vectors is 90
∘
.
Answered by
0
Answer:
answer is 90
Explanation:
above step is correct flow for more
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