Question

Find |AxB| if A=10, B=2 and A.B=12

Answer 1

You should know the values of Trigonometric functions of 53° and 37°
|AxB| do not use n^ dir not required
Modulus

Answer 2

The value of | A x B| would be 16

1) The given values are A= 10, B = 2 and A.B = 12

2) The formula for the dot product is :

A.B = A* B * cos x

where x is the angle subtended between the two vectors.

3) Substituting the values in this relation:

12 = 10*2* cos x

cos x = 12/20 = 3/5

x = 53 degrees

4) The formula for cross product is :

|A x B| = A*B* sin x

Substituting the values:

|A x B| = 10*2 * sin 53  = 10*2* 4/5 = 16