Math, asked by Anonymous, 26 days ago

Find B×A

❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ
❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ
❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​​​​​​​​​​​​​​​​​​​​

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Answers

Answered by tyrbylent
4

Answer:

Step-by-step explanation:

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Answered by telex
248

Question :-

Find B × A when,

A =  \begin{bmatrix}2 & 5 \\7& 0\end{bmatrix}

AND

B = \begin{bmatrix}6& 5 \\1& 1\end{bmatrix}

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Solution :-

Given Information :-

  • A =  \begin{bmatrix}2 & 5 \\7& 0\end{bmatrix}
  • B = \begin{bmatrix}6& 5 \\1& 1\end{bmatrix}

To Find :-

  • B × A

Concept :-

  • Matrices

Explanation :-

  • To multiply matrices, We have to multiply each term of its elements by each element of the other.
  • We will multiply rows and columns of first matrix with the rows and columns of other matrix.

Calculation :-

A =  \begin{bmatrix}2 & 5 \\7& 0\end{bmatrix}

AND

B = \begin{bmatrix}6& 5 \\1& 1\end{bmatrix}

⇒ B × A =  \begin{bmatrix}6 × 2 + 5 × 7 & 6 × 5 + 5 × 0\\1 × 2 + 1 × 7 & 1 × 5 + 1 × 0\end{bmatrix}

⇒ B × A =  \begin{bmatrix}47 & 30 \\9& 5\end{bmatrix}

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Final Answer :-

B × A =  \begin{bmatrix}47 & 30 \\9& 5\end{bmatrix}

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