Question

Find `B' if tan 3 B = sin45⁰. cos45⁰ + sin30⁰ .Where B is an acute angle.

Answer 1

Answer:

tan3B=sin45°×cos45°+sin30°

tan3B=1/√2×1/√2+1/2 (sin45°=1/√2) (cos45°=1/√2)

tan3B=1/2+1/2 (sin30°=1/2)

tan3B=1+1/2

tan3B=2/2

tan3B=1 (tan45°=1)

tan3B=tan45°

Now,

3B=45°

B=45/3

B=15°

Step-by-step explanation:

Hope this answer will help you.