Question

Find ∆B , if tan(A - B) = 1/√3 and sinA = √3/2 Also find cosB (A. B< 90").​

Answer 1

Answer:

√3/2

Step-by-step explanation:

sinA=√3/2   ⇒ sinA=sin60°  ⇒ A = 60°

Given,

tan(A - B) = 1/√3  ⇒ tan(A - B) = tan30°

     A - B = 30°

     60° - B = 30°           { A = 60° }

     30° = B

Hence, cosB = cos30° = √3/2

Answer 2

Required answer:-

Question:

• Find ∆B , if tan(A - B) = 1/√3 and sinA = √3/2 Also find cosB (A. B< 90").

Solution:

Given,

• tan(A-B) = 1/√3

• sinA = √3/2

To find:

• cosB

Step by step explaination:

tan (A-B) = tan30⁰

A-B = 30⁰

60⁰ - B = 30⁰

B = 30⁰

Therefore, cosB = cos30⁰ = √3/2