Question

find base of a triangle whose altitude is 20 cm and area is 0.8 square​

Answer 1

Step-by-step explanation:

tan (60) = 20/x

x = 20/√3 and

tan(60) = 20/y

y = 20/√3

Base = x +y = 20/√3 + 20/√3

= 40/√3 cm

Answer 2

Answer:

Given ,

h = 20 cm

Δ = 0.8 cm²

1/2 bh = 0.8

1/2 × b × 20 = 0.8

10b = 0.8

b = 0.08 cm

Hence , the length of the base will be 0.08 cm

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