find BC,area triangle ABC & BD if AB =4 &AC =5 ,angle Bis 90 , Angle CDB is also 90 degree?
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Answered by
0
Answer:
the question is only wrong please check your question
then also inam solving it
Step-by-step explanation:
△ABC is right angled △,∠B=90°
BD⊥AC
AB=3,AC=5
By Pythagoras theorem,
AB
2
+BC
2
=AC
2
⇒BC
2
=AC
2
−AB
2
=5
2
−3
2
⇒BC=4
In △ABC,
∠B=90°,AB=3,BC=4,AC=5
sinC=
AC
AB
=
5
3
→1
In △BDC
∠BDC=90°,BC=4
sinC=
BC
BD
→2
Comparing 1 and 2
5
3
=
4
BD
⇒BD=3.4
Answered by
0
Answer:
Then BC = √5²- 4² = √25 - 16 = √9 = 3
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