Question

find beta zeros of polynomial X square + 5 x + 8 then alpha beta
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Answer 1

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Here is your answer...

Given

$x {}^{2} + 5x + 8$

$\alpha + \beta = \frac{ - b}{a} = \frac{ - 5}{1} = - 5$

$\alpha \beta = \frac{c}{a} = \frac{8}{1} = 8$