Question

find both questions and send me our solution


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Answer 1

1. $\tan\theta$ = √3 , but , $\tan 60°$=√3
$\therefore \theta$= 60°
Hence, $\sin 60°$=√3/2 & $\cos 60°$=1/2
2. Since $\cos\theta$= Side Adjacent (Base) / Hypotenuse, $\therefore \cos\theta$= 3/5 Hence, Base=3k & Hypotenuse =5k
Now, $(Perpendicular)^2=(5k)^2 - (3k)^2$
$\implies (Perpendicular)^2 = (25k^2-9k^2) = 16k^2= (4k)^2$
$\implies Perpendicular = 4k$
Now $\since\sin\theta= Side Opposite (Perpendicular) / Hypotenuse,$$then \sin \theta = 4k/5k = 4/5$$and \tan\theta=\sin\theta/\cos \theta$$\therefore \tan\theta = (4/5)/(3/5) =4/3$
Now put these values in the Equation and you'll get the answer.
It is not clear whether it is cot or cos in the question. So substitute it yourself.