FIND BP
THIS SUM IS FROM SIMILARITIES
PLZ HELP
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Since it’s a right triangle because it bisects AC at P we can say:
BC^2 = BP^2 + PC^2 (By Pythagoras Theorem)
(4)^2= 2^2 + BP^2
16 = 4 + BP^2
12 =BP^2
BP = Root 12
BC^2 = BP^2 + PC^2 (By Pythagoras Theorem)
(4)^2= 2^2 + BP^2
16 = 4 + BP^2
12 =BP^2
BP = Root 12
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