find bracket root 4 + root 4 (square find bracket root 4 + root 4 square
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Step-by-step explanation:
Simplify: \mathbf{\color{green}{ \sqrt{3\,} + 4\,\sqrt{3\,} }}3+43
The radical part is the same in each term, so I can do this addition. To help me keep track that the first term means "one copy of the square root of three", I'll insert the "understood" "1":
\sqrt{3\,} + 4\,\sqrt{3\,} = 1\,\sqrt{3\,} + 4\,\sqrt{3\,}3+43=13+43
= (1 + 4)\,\sqrt{3\,}=(1+4)3
= \mathbf{\color{purple}{ 5\,\sqrt{3\,} }}=53
Don't assume that expressions
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