Question

find by cross multiplication 2x×7y-16=0 and 10x+y-12=0​

Answer 1

Answer:

Given that

2x+7y-=0

and 10x+y-12=0

by multiplying

(2×19)x^1+1 + (7×1)y^1+1 -(16)(-12)=0

38

$38{x}^{2} + 7y { }^{2} + 192 = 0$

which is required Answer

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