Question

Find C.I. for rupees 9000 in 3 years at 10%pa.

STD 8
I need step by Step answer​

Answer 1

Answer:

A = 9000 × (1 + 12100 ) (1 + 15100 ) (1 + 20100 ) A = 9000 × 112100 × 115100 × 120100 A = 112 × 115 × 12 × 9100 A = 13910.40 Rs

Answer 2

Answer:

Rs.11979

Step-by-step explanation:

C.I.=?

time(n) =3years

rate(r) =10%p.a.

P=₹9000

As CI=$P {(1+\frac{r}{100} )}^{n}$

so you can easily put value find the answers

and so when we put the given values....

=   $9000{(1+\frac{10}{100} )}^{3}$

=   $9000{(\frac{11}{10} )}^{3}$

=   $9000(\frac{11}{10} )(\frac{11}{10} )(\frac{11}{10})$

all zeros will be canceled and 9 will be multiplied by 1331 which is Rs.11979