Question

Find C.I. for rupees 9000 in 3 years at 10%pa.

STD 8
need step by step ANS
plz attach photos answer​

Answer 1

Solution:-

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ANSWER:-

• Amount is Rs 11,979.
• Compound Interest is Rs 2,979.

GIVEN:-

• Principal (P) = ₹ 9000
• Rate (R) = 10% p.a
• Time (T) = 3 years

TO FIND:-

• Compound Interest = ?

FORMULA:-

$\to\sf{Amount\:(A)=P \bigg(1+\frac{R}{100} \bigg)^{n}}$

$\to \sf{Compound \: Interest \: (CI) = Amount - Principal}$

SOLVING BY APPLYING THE FORMULA:-

• Amount = $\to\sf{P\bigg(1+\dfrac{R}{100}\bigg)^{n}}$
• Amount = $\to\sf{9000\bigg(1+\dfrac{10}{100}\bigg)^{3}}$
• Take LCM
• LCM = 100
• Amount = $\to\sf{9000\bigg(\dfrac{100 + 10}{100}\bigg)^{3}}$

• Amount = $\to\sf{9000\bigg(\dfrac{110}{100}\bigg)^{3}}$

• Amount = $\to\sf{9000\bigg(\dfrac{1331000}{1000000}\bigg)}$

• Amount = $\to\sf{9000\times\dfrac{1331000}{1000000}}$

• Amount = $\to\sf{9{\not{000}}\times\dfrac{1331{\not{000}}}{1{\not{000000}}}}$

• Amount = $\to\sf{9}\times\dfrac{1331}{1}$

• Amount = $\to\sf{9}\times{1331}$

• Amount = $\to\sf{9}\times{1331} = 11979$

• Amount = Rs 11,979

Amount is Rs 11,979.

• Compound Interest (CI) = Amount - Principal
• Compound Interest (CI) = 11,979 - 9000
• Compound Interest (CI) = 11,979 - 9000 = 2,979
• Compound Interest (CI) = Rs 2,979

So, compound interest is Rupees 2,979.

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