Find C.I on sum of 100000 for1×1/2 years at 8% per annum compounded half yearly
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Given. P=100000
time(n)=1×(1\2)
=3\2
R=8%
Because compounded half yearly
so, we are doing
n =2×n , R=R\2
n=3 , R=4%
we know that
A=P(1+R\100)^n
=100000(1+4\100)^3
=100000(1+25)^3
=100000(26\25)^3
=100000(1.124864)
A =112486.4
Hence. c.I.=A-P
=112486.4-100000
=12486.4
time(n)=1×(1\2)
=3\2
R=8%
Because compounded half yearly
so, we are doing
n =2×n , R=R\2
n=3 , R=4%
we know that
A=P(1+R\100)^n
=100000(1+4\100)^3
=100000(1+25)^3
=100000(26\25)^3
=100000(1.124864)
A =112486.4
Hence. c.I.=A-P
=112486.4-100000
=12486.4
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