Question

find c, if the quadratic equation x²-2(c+1)x+c²= 0 has real and equal root​

Answer 1

Answer:

value of c = -1/2

Step-by-step explanation:

Compare given Quadratic equation x²-2(c+1)x+c²=0 with

Ax²+Bx+C=0 , we get

A = 1, B = -2(c+1), C = c²,

Discreminant (D) = 0

/Since , roots are real and equal*/

=> B²-4AC = 0

=> [-2(c+1)]²-4×1×c² = 0

=> 4(c+1)² - 4c² = 0

=> (c+1)² - c² = 0

=> c²+2c+1-c² = 0

=> 2c+1=0

=> 2c = -1

=> c = -1/2

Therefore,

value of c = -1/2

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