Find center and radius of circle 3x2+3y2-5x-6y+4=0
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centre (-g,-f) of circle
we know the general equation of circle as
ax^2+by^2+2gx+2fy+c=0
now compare-
2g=-5. 2f=-6
g=-5/2 f=-3
(g,f)=(-5/2,-3)
for centre (-g,-f)=(5/2,3) is the centre.
for radius use the formula
r= square root of (g^2+f^2-c)
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