Question

Find center and radius of given equation
7x²+ 7y² + 2x-3y + 2 = 0​

Answer 1

Answer:

center and radius of given equation

7x²+ 7y² + 2x-3y + 2 = 0

x²+ y² + 2/7 x - 3/7 y + 2/7 = 0

${(x + \frac{1}{7}) }^{2} + {(y - \frac{3}{14}) }^{2} \\ + \frac{2}{7} - \frac{1}{49} - \frac{9}{196} = 0 \\ \\ {(x + \frac{1}{7}) }^{2} + {(y - \frac{3}{14}) }^{2} \\ + \frac{56 - 4 - 9}{196} = \frac{43}{196}$

So, center is,

(-1/7, 3/14)

Radius

$\frac{ \sqrt{43} }{14}$