find centre and radius of circle from the given equation=2x^2+2y^2-x=0
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The equation of the given circle is 2x2 + 2y2 – x = 0. which is of the form (x – h)2 + (y – k)2 = r2, where h = 1/4, k = 0 and r = 1/4. Thus, the centre of the given circle is (1/4, 0), while its radius is 1/4.09-Feb-2018
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