Find centre of mass of three particles at the vertices of an equilateral triangle. The masses of the particle are 10g, 20g, and 30g respectively. Each side of the equilateral triangle is 0.5 m long.
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Answer:
Explanation:
Given that,
m
1
=100g
m
2
=150g
m
3
=200g
a = 0.5 m = 50 cm
Now, according to diagram
Center of mass coordinates
X
cm
=
450
0×100+150×50+200×25
X
cm
=
450
7500+5000
X
cm
=27.8cm
X
cm
=0.28m
Now,
Y
cm
=
450
0×100+0×150+
3
×25×200
Y
cm
=
450
8660.3
Y
cm
=19.2cm
Y
cm
=0.2m
Hence, the center of mass of three particles at the vertices of an equilateral triangle is X
cm
=0.28cm and Y
cm
=0.2cm respectively
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