Question

find centroid of triangle where vertices are A(0,0,0), B(1,2,3), C(5,7,9)

Answer 1

Answer:

centroid of triangle

(0+1+5/3,0+2+7/3,0+3+9/3)

(6/3,9/3,12/3)

(2,3,4)

Answer 2

Step-by-step explanation:

Given:-

The vertices of a triangle are A(0,0,0), B(1,2,3), C(5,7,9)

To find:-

find centroid of triangle where vertices are A(0,0,0), B(1,2,3), C(5,7,9)?

Solution:-

The vertices of a triangle are A(0,0,0), B(1,2,3), C(5,7,9)

Let (x1,y1,z1)= (0,0,0)

x1 = 0

y1 = 0

z1 = 0

Let (x2, y2,z2) = (1,2,3)

x2 = 1

y2 = 2

z2 = 3

Let (x3, y3,z3) = (5,7,9)

x3 = 5

y3 = 7

z3 = 9

We know that

The Centroid of a triangle whose vertices are

(x1, y1,z1) ; (x2, y2,z2) and (x3, y3,z3) is

[(x1+x2+x3)/3 , (y1+y2+y3)/3 , (z1+z2+z3)/3]

Centroid=[(0+1+5)/3 ,(0+2+7)/3 , (0+3+9)/3]

=>Centroid = (6/3 , 9/3 , 12/3)

Therefore,Centroid = (2,3,4)

Answer:-

The centroid of the triangle is (2,3,4)

Used formula:-

The Centroid of a triangle whose vertices are (x1, y1,z1) ; (x2, y2,z2) and (x3, y3,z3) is [(x1+x2+x3)/3 , (y1+y2+y3)/3 ,(z1+z2+z3)/3]