find centroid of triangle whose vertices are (3,4) (-7,-2) and(10,-5)
Answers
Answered by
1
Answer:
Given, vertices of triangle (3,4) (-7,-2) and(10,-5)
We know Centroid of triangle is given by :
C(x,y) = [ ( x1+x2+x3 )/3 , ( y1+y2+y3 )/3 ]
=> C(x,y) = [ ( 3+(-7)+10 )/3 , ( 4+(-2)+(-5) )/3 ]
= [ ( 3-7+10 )/3 , ( 4-2-5 )/3 ]
= [ 6/3 , -3/3 ]
C( x , y ) = ( 2 , -1 )
Similar questions