Question

Find change in ke of body when its momentum is increased by 50%

Answer 1

Kinetic energy K and linear momentum P are related as

K=P22m………(1)K=P22m………(1)

The new momentum is P+50% 0f P =(3/2)P.

If the new kinetic energy is K’ then

K′=(3/2)P22m=94p22m………(2)K′=(3/2)P22m=94p22m………(2)

Divide equation (2) by Equation (1) to get

K′=(9/4)KK′=(9/4)K

Now the % change in K is

K′−KK100=(9/4)K−KK100=K′−KK100=(9/4)K−KK100= 125%