Physics, asked by kshafin714, 8 months ago

Find change in velocity when Acceleration of 10m/square second and time is 2 min​

Answers

Answered by MrAadil
0

Change in Velocity = t × a

= 10 × 2

= 20

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Answered by saptarshidawn06
0

Answer:

We can answer it in two ways……

1st…..

As initial velocity is not given…so assume it to be zero i.e. rest position

And a=10 m/s^2 ( acceleration =change in velocity w.r.t time)

That means …..after each second velocity will increase by 10.

At time… t=0……v=0

At t=1 second….v=10m/s ( increased by 10)

At t=2second……v= 20 m/s( again increased by 10)

At t=3 second ….. v=30m/s (again incresesd by 10)

And this is our required velocity i.e.after 3 second.

2nd …

Just use the 1st equation of motion ,

v=u +at

As u =0 ( intial velocity ) , a= 10m/s^2 , t= 3sec.

Putting all the values…

v= 0 +10×3

v= 30 m/s.

Explanation:

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