Math, asked by irfan9751, 6 months ago

Find CI on Rs 12600 for 2 years at 10% per annum compounded annually.​

Answers

Answered by Anonymous
94

\Huge\sf\red{\underline{\underline{Given}}} \::\\

\begin{cases}\sf\gray{Principal = 12600} \\ \sf\gray{Time = 2\: Years} \\\sf\gray{Rate = 10\%\:per\:annum}\end{cases} \\\\

\Huge\sf\blue{\underline{\underline{To\:Find}}}\:: \\

\begin{cases}\sf\gray{Compound \: Interest}\end{cases} \\\\

\Huge\sf\pink{\underline{\underline{Solution}}}\:: \\\\

\boxed{ \sf{\orange{ A = P \bigg(1 + \frac{r}{100}\bigg)^n }}} \\\\

\leadsto\:\:\: \sf \purple {A = 12600 \bigg(1 + \dfrac{10}{100}\bigg)^2} \\\\

\leadsto\:\:\: \sf \green {12600 \bigg(1 + \dfrac{1}{10}\bigg)^2} \\\\

\leadsto\:\:\: \sf \purple {12600 \bigg(\dfrac{10 + 1}{10}\bigg)^2} \\\\

\leadsto\:\:\: \sf \green {12600 \bigg(\dfrac{11}{10}\bigg)^2} \\\\

\leadsto\:\:\: \sf \purple {12600 \times \dfrac{121}{100}} \\\\

\leadsto\:\:\: \sf \green {126 \times 121} \\\\

\leadsto\:\:\: \underline \mathsf \purple {15246} \\\\

\star\:\sf\underline\red{ Amount \: after \: 2 \: years  = Rs\:15,246}\\\\

\Large\sf\gray{ Now,} \\

\boxed{ \sf{\orange{ Amount \: = \: Principal \: + \: Interest }}} \\\\

\leadsto\:\:\:\mathsf \purple {15246 \: = \: 12600 \:  + \: Interest} \\\\

\leadsto\:\:\:\mathsf \green {15246\: - \:12600 \: =\:  Interest} \\\\

\leadsto\:\:\: \mathsf \purple {2646 \: = \:Interest} \\\\

\leadsto\:\:\:\underline \mathsf \green {Interest \: = \: 2646} \\\\

\star\:\sf\underline\red{Hence,\: Compound\: Interest \:=\:Rs\:2,646}

Answered by khansaaiqa
4

Answer:

go through the file attached

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