Question

Find CI on Rs 12600 for 2 years at 10% per annum compounded annually

Answer 1

Answer:

2520

Step-by-step explanation:

ci=prt/100

where,

p=12600

r=10%

t=2

put the value in formula

ci=12600×2×10/100

ci=2520

Answer 2

Solution:-

$\sf \bold{We \: have \: A = P(1 + \frac{R}{100} {)}} \mathbb{^{n} } \\ \sf \small \red{\:Principal(P) = 12600 } \\ \sf \small \red{Rate(R) = 10\%} \\ \sf \small \red{Number \: of \: years} \mathbb \red{(n) } \sf \small \red{ = 2}$

$\sf \orange{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 12600(1 + \frac{10}{100} {)}^{2} = 12600( \frac{11}{10 } {)}^{2} }$

$\sf \orange{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 12600 \times \frac{11}{10} \times \frac{11}{10} = 15246}$

$\sf{CI =A - P = 15246 - 12600 =2646}$

More:-

$\sf \small{(i)Amount \: when \: interest \: is \: compunded annually}$

$\sf \small\orange{ = p( 1 + \frac{r}{100} {)}^{n} }$

$\sf \small{(i)Amount \: when \: interest \: is \: compounded \: half \: yearly}$

$\sf \small \orange{ = p(1 + \frac{r}{200} {)}^{2n} }$