Question

find CI on rupees 12600 for 2 years at 10% per annum compound annually
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Answer 1

$\huge\tt{Required\:Answer:}$

1. We have, A = P ( 1 + R / 100 ).
2. Principal (P) => 12600.
3. Rate (R) => 10.
4. Number of years (N) => 2 years.

$= > 12600 (1 + \frac{10}{100} ) {}^{2} = 12600 \: ( \frac{11}{10} ) {}^{2} \\ = > 12600 \times \frac{11}{10} \times \frac{11}{10 } = 15246$

Formula :- [ CI = A - P ]

= 15246 - 12600

= 2646

Answer 2

Answer:

★ Compound interest = Rs 2,646 ★

Step-by-step explanation:

Given:

• Principal is 12,600
• Time is 2 years
• Rate is 10% per annum

To Find:

• Compound interest

Solution:

★ We know that the formula for finding Amount is = P ( 1 + r/100)^n

A/q

→ A = 12,600 ( 1 + 10/100)²

→ A = 12,600 (110/100)²

→ A = 12,600 x 110/100 x 110/100 ( after cancelling all the terms)

→A = 126 x 121

→ Amount = Rs 15,246

★ C.I = ( Amount – Principal)

→ C.I = (15,246 – 12,600)

→ C.I = Rs 2,646

Hence, The C.I will be Rs 2,646