Question

Find circumcentre of triangle whose vertices are ;- ( - 2 , 3 ) , ( - 1 , 0 ) , ( 7 , - 6 ) .

Answer 1

Answer:

circumference of triangle=(10+√10+√90) units

Step-by-step explanation:

circumference=perimeter.., n perimeter of triangle=sum of all sides..,

let the points be A(-2,3), B(-1,0), C(7,-6)

using distance,,.

i.e= √ (x2 − x1)^2 + (y2 − y1)^2

first let us find AB=? n BC=? AC=?

AC= √(-2-7)^2+(-3+6)^2

i.e=√81+9=√90 units

similarly for BC=10 units..,AB=√10 units..

hence circumference of triangle=(10+√90+√10) units