Find class interval of following data.
Mid value of frequency
2. 3 2
6
4. 4
6
8
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We know that , if m is the midpoint fo a class and h is the class size,
then lower limit of class interval =m−
2
h
Upper limit of class interval =m+
2
h
We have class sixe, 15−5=10
so the class interval formed from the midpoint 5 is
=(5−
2
10
)−(5+
2
10
)i.e0−10
Containing in the same manner, the continuous classes formed are;
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