Question

find common difference AP whose nth term is(3-2n) ​

Answer 1

Answer:

let’s prove

1st=3−2(1)=3−2=1

2nd=3−2(2)=3−4=−1

4th=3−2(4)=3−8=−5

5th=3−2(5)=3−10=−7

Common Difference is

d=d2−d1=d5−d4

d=−1−1=−7−(−5)

thank you

May God bless you

Answer 2

Answer:

-2

Step-by-step explanation:

an=3-2n

a1=3-2(1) = 1

a2=3-2(2)= -1

a3=3-2(3)= -3

so AP is 1,-1,-3......

hence d= -1-1

=-2